Processing Math: 76%
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.

jsMath

Solution 4.4:5b

From Förberedande kurs i matematik 1

Revision as of 11:06, 1 October 2008 by Ian (Talk | contribs)
Jump to: navigation, search

Let's first investigate when the equality


tanu=tanv


is satisfied. Because u can be interpreted as the slope (gradient) of the line which makes an angle u with the positive x -axis, we see that for a fixed value of tan u, there are two angles v in the unit circle with this slope:


v=u and v=u+


slope = tan u slope = tan u


The angle v has the same slope after every half turn, so if we add multiples of to u, we will obtain all the angles v which satisfy the equality


v=u+n


where n is an arbitrary integer.

If we apply this result to the equation


tanx=tan4x


we see that the solutions are given by


\displaystyle 4x=x+n\pi ( \displaystyle n an arbitrary integer),

and solving for \displaystyle x gives


\displaystyle x=\frac{1}{3}n\pi ( \displaystyle n an arbitrary integer).