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Solution 4.4:5c

From Förberedande kurs i matematik 1

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For a fixed value of u, an equality of the form


cosu=cosv


is satisfied by two angles v in the unit circle:


v=u and v=u


This means that all angles v which satisfy the equality are


v=u+2n and v=u+2n


where n is an arbitrary integer.

Therefore, the equation


cos5x=cosx+5 


has the solutions


5x=x+5+2n or

5x=x5+2n

If we collect x onto one side, we end up with


x=20+21nx=30+31n  ( n an arbitrary integer).