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Solution 3.3:3h

From Förberedande kurs i matematik 1

Revision as of 07:04, 2 October 2008 by Tek (Talk | contribs)
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Because a2a=a2a12=a2+12=a52 , the logarithm law, blga=lgab, gives that

logaa2a=logaa52=25logaa=251=25 

where we have used that logaa=1.


Note: In this exercise, we assume, implicitly, that a0 and a=1.