Solution 4.3:3e

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The angle \displaystyle \frac{\pi }{2}+v makes the same angle with the positive \displaystyle y -axis as the angle \displaystyle v makes with the positive \displaystyle x -axis, and hence we see that the \displaystyle x -coordinate for \displaystyle \frac{\pi }{2}+v is equal to the \displaystyle y -coordinate for \displaystyle v, but with a change of sign, i.e.


\displaystyle \cos \left( \frac{\pi }{2}+v \right)=-\sin v=-a


angle \displaystyle v angle \displaystyle \frac{\pi }{2}+v