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Solution 4.4:5c

From Förberedande kurs i matematik 1

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For a fixed value of u, an equality of the form

cosu=cosv

is satisfied by two angles v in the unit circle,

v=uandv=u.

This means that all angles v which satisfy the equality are

v=u+2nandv=u+2n

where n is an arbitrary integer.

Therefore, the equation

cos5x=cos(x+5)

has the solutions

5x5x=x+5+2nor=x5+2n.

If we collect x onto one side, we end up with

xx=20+2n=30+3n

where n is an arbitrary integer.