2.2 Exercises
From Förberedande kurs i matematik 1
Övning 2.2:1
Lös ekvationerna
| a) | \displaystyle x-2=-1 | b) | \displaystyle 2x+1=13 |
| c) | \displaystyle \displaystyle\frac{1}{3}x-1=x | d) | \displaystyle 5x+7=2x-6 |
Svar
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Lösning a
Lösning b
Lösning c
Lösning d
Övning 2.2:2
Lös ekvationerna
| a) | \displaystyle \displaystyle\frac{5x}{6}-\displaystyle\frac{x+2}{9}=\displaystyle\frac{1}{2} | b) | \displaystyle \displaystyle\frac{8x+3}{7}-\displaystyle\frac{5x-7}{4}=2 |
| c) | \displaystyle (x+3)^2-(x-5)^2=6x+4 | d) | \displaystyle (x^2+4x+1)^2+3x^4-2x^2=(2x^2+2x+3)^2 |
Svar
Lösning a
Lösning b
Lösning c
Lösning d
Övning 2.2:3
Lös ekvationerna
| a) | \displaystyle \displaystyle\frac{x+3}{x-3}-\displaystyle\frac{x+5}{x-2}=0 |
| b) | \displaystyle \displaystyle\frac{4x}{4x-7}-\displaystyle\frac{1}{2x-3}=1 |
| c) | \displaystyle \left(\displaystyle\frac{1}{x-1}-\frac{1}{x+1}\right)\left(x^2+\frac{1}{2}\right)=\displaystyle\frac{6x-1}{3x-3} |
| d) | \displaystyle \left(\displaystyle\frac{2}{x}-3\right)\left(\displaystyle\frac{1}{4x}+\frac{1}{2}\right)-\left(\displaystyle\frac{1}{2x}-\frac{2}{3}\right)^2-\left(\displaystyle\frac{1}{2x}+\frac{1}{3}\right)\left(\displaystyle\frac{1}{2x}-\frac{1}{3}\right)=0 |
Svar
Lösning a
Lösning b
Lösning c
Lösning d
