From Förberedande kurs i matematik 1
Exercise 2.1:1
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a)
| 3x(x−1)
| b)
| (1+x−x2)xy
| c)
| −x2(4−y2)
|
d)
| x3y2 y1−1xy+1
| e)
| (x−7)2
| f)
| (5+4y)2
|
g)
| (y2−3x3)2
| h)
| (5x3+3x5)2
|
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Exercise 2.1:2
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a)
| (x−4)(x−5)−3x(2x−3)
| b)
| (1−5x)(1+15x)−3(2−5x)(2+5x)
|
c)
| (3x+4)2−(3x−2)(3x−8)
| d)
| (3x2+2)(3x2−2)(9x4+4)
|
e)
| (a+b)2+(a−b)2
|
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Exercise 2.1:3
Factorise and simplify as much as possible
a)
| x2−36
| b)
| 5x2−20
| c)
| x2+6x+9
|
d)
| \displaystyle x^2-10x+25
| e)
| \displaystyle 18x-2x^3
| f)
| \displaystyle 16x^2+8x+1
|
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Exercise 2.1:4
Determine the coefficients in front of \displaystyle \,x\, and \displaystyle \,x^2\ when the following expressions are expanded out.
a)
| \displaystyle (x+2)(3x^2-x+5)
|
b)
| \displaystyle (1+x+x^2+x^3)(2-x+x^2+x^4)
|
c)
| \displaystyle (x-x^3+x^5)(1+3x+5x^2)(2-7x^2-x^4)
|
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Exercise 2.1:5
Simplify as much as possible
a)
| \displaystyle \displaystyle \frac{1}{x-x^2}-\displaystyle \frac{1}{x}
| b)
| \displaystyle \displaystyle \frac{1}{y^2-2y}-\displaystyle \frac{2}{y^2-4}
|
c)
| \displaystyle \displaystyle \frac{(3x^2-12)(x^2-1)}{(x+1)(x+2)}
| d)
| \displaystyle \displaystyle \frac{(y^2+4y+4)(2y-4)}{(y^2+4)(y^2-4)}
|
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Exercise 2.1:6
Simplify as much as possible
a)
| \displaystyle \left(x-y+\displaystyle\frac{x^2}{y-x}\right) \displaystyle \left(\displaystyle\frac{y}{2x-y}-1\right)
| b)
| \displaystyle \displaystyle \frac{x}{x-2}+\displaystyle \frac{x}{x+3}-2
|
c)
| \displaystyle \displaystyle \frac{2a+b}{a^2-ab}-\frac{2}{a-b}
| d)
| \displaystyle \displaystyle\frac{a-b+\displaystyle\frac{b^2}{a+b}}{1-\left(\displaystyle\frac{a-b}{a+b}\right)^2}
|
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Exercise 2.1:7
Simplify the following by writing them as a single ordinary fraction
a)
| \displaystyle \displaystyle \frac{2}{x+3}-\frac{2}{x+5}
| b)
| \displaystyle x+\displaystyle \frac{1}{x-1}+\displaystyle \frac{1}{x^2}
| c)
| \displaystyle \displaystyle \frac{ax}{a+1}-\displaystyle \frac{ax^2}{(a+1)^2}
|
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Exercise 2.1:8
Simplify the following fractions by writing them as a single ordinary
a)
| \displaystyle \displaystyle \frac{\displaystyle\ \frac{x}{x+1}\ }{\ 3+x\ }
| b)
| \displaystyle \displaystyle \frac{\displaystyle \frac{3}{x}-\displaystyle \frac{1}{x}}{\displaystyle \frac{1}{x-3}}
| c)
| \displaystyle \displaystyle \frac{1}{1+\displaystyle \frac{1}{1+\displaystyle \frac{1}{1+x}}}
|
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