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\displaystyle Ta\sin45^\circ -Mga=0; \displaystyle T=Mg\sqrt{2}

\displaystyle H-T\cos45^\circ =0; \displaystyle H=Mg\sqrt{2} \cdot 1/\sqrt{2}; \displaystyle H=Mg

\displaystyle V+T\sin45^\circ –Mg=0 \displaystyle \Rightarrow \displaystyle V=Mg\sqrt{2}\cdot 1/\sqrt{2}–Mg=0