Svar 2.2:2

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\displaystyle \mathbf R=[(300\cos50^\circ –400\cos80^\circ )\mathbf e_x+(300\sin50^\circ +400\sin80^\circ )\mathbf e_y] \,\mathrm N
\displaystyle =[(192,84–69,46)\mathbf e_x+(229,81+393,92)\mathbf e_y)] \,\mathrm N=(123,38 \mathbf e_x+623,73 \mathbf e_y) \,\mathrm N