Svar 2.2:6
FörberedandeFysik
\displaystyle \displaystyle \mathbf{e}_F = \frac{\mathbf{F}}{F} = \frac{(6,10)\,\textrm{N}}{\sqrt{6^2+10^2}\,\textrm{N}} = \frac{(6,10)}{\sqrt{136}} = \frac{(6,10)}{11,66}
eller
\displaystyle \displaystyle \mathbf{e}_F = -\frac{\mathbf{F}}{F}