Lösning 2.6:6
FörberedandeFysik
(Skillnad mellan versioner)
Rad 3: | Rad 3: | ||
<math>H-T\cos45^\circ =0</math>; <math>H=Mg\sqrt{2} \cdot 1/\sqrt{2}</math>; <math>H=Mg</math> | <math>H-T\cos45^\circ =0</math>; <math>H=Mg\sqrt{2} \cdot 1/\sqrt{2}</math>; <math>H=Mg</math> | ||
- | <math>V+T\sin45^\circ –Mg=0</math> | + | <math>V+T\sin45^\circ –Mg=0</math> <math>\Rightarrow</math> <math>V=Mg\sqrt{2}\cdot 1/\sqrt{2}–Mg=0 </math> |
Nuvarande version
\displaystyle Ta\sin45^\circ -Mga=0; \displaystyle T=Mg\sqrt{2}
\displaystyle H-T\cos45^\circ =0; \displaystyle H=Mg\sqrt{2} \cdot 1/\sqrt{2}; \displaystyle H=Mg
\displaystyle V+T\sin45^\circ –Mg=0 \displaystyle \Rightarrow \displaystyle V=Mg\sqrt{2}\cdot 1/\sqrt{2}–Mg=0