FörberedandeFysik

\displaystyle Ta\sin45^\circ -Mga=0 \displaystyle T=Mg\sqrt{2}

\displaystyle H-T\cos45^\circ =0 \displaystyle H=Mg\sqrt{2} \cdot 1/\sqrt{2} \displaystyle H=Mg

\displaystyle V+T\sin45^\circ –Mg=0 \displaystyle V=Mg\sqrt{2}\cdot 1/\sqrt{2}–Mg=0