Lösning 2.6:6

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Nuvarande version (22 december 2017 kl. 15.24) (redigera) (ogör)
 
Rad 3: Rad 3:
<math>H-T\cos45^\circ =0</math>; <math>H=Mg\sqrt{2} \cdot 1/\sqrt{2}</math>; <math>H=Mg</math>
<math>H-T\cos45^\circ =0</math>; <math>H=Mg\sqrt{2} \cdot 1/\sqrt{2}</math>; <math>H=Mg</math>
-
<math>V+T\sin45^\circ –Mg=0</math>; <math>V=Mg\sqrt{2}\cdot 1/\sqrt{2}–Mg=0 </math>
+
<math>V+T\sin45^\circ –Mg=0</math> <math>\Rightarrow</math> <math>V=Mg\sqrt{2}\cdot 1/\sqrt{2}–Mg=0 </math>

Nuvarande version

\displaystyle Ta\sin45^\circ -Mga=0; \displaystyle T=Mg\sqrt{2}

\displaystyle H-T\cos45^\circ =0; \displaystyle H=Mg\sqrt{2} \cdot 1/\sqrt{2}; \displaystyle H=Mg

\displaystyle V+T\sin45^\circ –Mg=0 \displaystyle \Rightarrow \displaystyle V=Mg\sqrt{2}\cdot 1/\sqrt{2}–Mg=0