Answer 3.1:8
From Förberedande kurs i matematik 1
| a) | \displaystyle \sqrt[\scriptstyle3]6 > \sqrt[\scriptstyle3]5 | b) | \displaystyle 7 > \sqrt7 |
| c) | \displaystyle \sqrt7 > 2{,}5 | d) | \displaystyle \sqrt[\scriptstyle3]2\cdot3 > \sqrt2\bigl(\sqrt[\scriptstyle4]3\,\bigr)^3 |
