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Solution 1.1:2a

The expression consists of two brackets

\displaystyle \bbox[#FFEEAA;,1.5pt]{\,(3-(7-4))\,}\cdot\bbox[#FFEEAA;,1.5pt]{\,(6-5)\,}

which we can work out individually and then multiply together. In the expression in the first bracket, we calculate the inner bracket first

\displaystyle (3-\bbox[#FFEEAA;,1.5pt]{\,(7-4)\,}) = (3-\bbox[#FFEEAA;,1.5pt]{\,3\,})

and obtain that the expression in the first bracket becomes \displaystyle 3-3=0.

The complete expression is 0 times \displaystyle (6-5), and since 0 times anything is always 0 the answer is 0.