Solution 2.2:6b
From Förberedande kurs i matematik 1
Because the point of intersection lies on both lines, it must satisfy the equations of both lines
\displaystyle y=-x+5\qquad\text{and}\qquad x=0\,, |
where \displaystyle x=0 is the equation of the y-axis. Substituting the second equation, \displaystyle x=0, into the first equation gives \displaystyle y=-0+5=5. This means that the point of intersection is (0,5).
![Image:2_2_6_b.gif](/wikis/2008/bridgecourse1-ImperialCollege/img_auth.php/e/e8/2_2_6_b.gif)