Solution 2.2:6d
From Förberedande kurs i matematik 1
At the point where the lines cut each other, we have a point that lies on both lines and which must therefore satisfy the equations of both lines,
\displaystyle x+y+1=0\qquad\text{and}\qquad x=12\,\textrm{.} |
We obtain the solution to this system of equations by substituting \displaystyle x=12 into the first equation
\displaystyle 12+y+1=0\quad\Leftrightarrow\quad y=-13\,\textrm{,} |
which gives us the point of intersection as (12,-13).