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Solution 4.1:6a

From Förberedande kurs i matematik 1

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m (Lösning 4.1:6a moved to Solution 4.1:6a: Robot: moved page)
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If we write the equation as
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<math>\left( x-0 \right)^{2}+\left( y-0 \right)^{2}=9</math>
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we can interpret the left-hand side as the square of the distance between the points
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<math>\left( x \right.,\left. y \right)</math>
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and
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<math>\left( 0 \right.,\left. 0 \right)</math>.
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The whole equation says that the distance from a point (
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<math>\left( x \right.,\left. y \right)</math>
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to the origin should be constant and equal to
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<math>\sqrt{9}=3</math>, which describes a circle with its centre at the origin and radius
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<math>\text{3}</math>.
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<center> [[Image:4_1_6_a.gif]] </center>
<center> [[Image:4_1_6_a.gif]] </center>
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<center> [[Image:4_1_6a.gif]] </center>
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Revision as of 11:27, 27 September 2008

If we write the equation as


x−02+y−02=9 


we can interpret the left-hand side as the square of the distance between the points xy  and 00 . The whole equation says that the distance from a point ( xy  to the origin should be constant and equal to 9=3 , which describes a circle with its centre at the origin and radius 3.


Image:4_1_6_a.gif


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