Solution 4.4:2e

From Förberedande kurs i matematik 1

This is almost the same equation as in exercise d. First, we determine the solutions to the equation when 05x2, and using the unit circle shows that there are two of these: 5x =6 and 5x =−6=65.

We obtain the remaining solutions by adding multiples of 2 to the two solutions above:

5x =6+2n and 5x =65+2n ( n an arbitrary integer),

or if we divide by 5:

x =30+52n and x =6+52n ( n an arbitrary integer).