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Solution 2.2:6b

From Förberedande kurs i matematik 1

Revision as of 13:04, 24 September 2008 by Tek (Talk | contribs)
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Because the point of intersection lies on both lines, it must satisfy the equations of both lines

y=x+5andx=0

where x=0 is the equation of the y-axis. Substituting the second equation, x=0, into the first equation gives y=0+5=5. This means that the point of intersection is (0,5).


Image:2_2_6_b.gif