Processing Math: Done
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.

jsMath

Solution 8.6b

From Mechanics

(Difference between revisions)
Jump to: navigation, search
Line 20: Line 20:
<math>\sqrt{{{7}^{2}}+{{\left( -6 \right)}^{2}}}=\sqrt{13}=3\textrm{.}6\ \text{m}</math>
<math>\sqrt{{{7}^{2}}+{{\left( -6 \right)}^{2}}}=\sqrt{13}=3\textrm{.}6\ \text{m}</math>
 +
 +
In the second part the boat travel with constant velocity <math>6\mathbf{i}-8\mathbf{j}</math>
 +
 +
 +
 +
Thus during the first part the boat has travelled a distance 3.6 m.
Thus during the first part the boat has travelled a distance 3.6 m.

Revision as of 19:57, 14 April 2010

Here we use

r=21(u+v)t+r0

in the first part.

According to the text

u=i+2j

v=6i8j

We assume the starting point is the origin so that r0=0.

At t=10

r=21(i+2j+6i8j)t=(3.5i3j)10=35i30j=(7i6j)5

The distance is the magnitude of this vector

72+62=13=3.6 m 

In the second part the boat travel with constant velocity 6i8j



Thus during the first part the boat has travelled a distance 3.6 m.