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Solution 19.8d

From Mechanics

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(New page: The expression for the position vector <math>\mathbf{r}</math> has been obtained in part b). <math>\mathbf{r}=\left( 40t \right)\mathbf{i}+\left( -2t+400 \right)\mathbf{j}</math>)
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<math>\mathbf{r}=\left( 40t \right)\mathbf{i}+\left( -2t+400 \right)\mathbf{j}</math>
<math>\mathbf{r}=\left( 40t \right)\mathbf{i}+\left( -2t+400 \right)\mathbf{j}</math>
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If the aeroplane is due east of the origin its position in the north-south direction must be zero, which means the <math>\mathbf{j}</math> component of the position vector must be zero.
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<math>\begin{align}
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& -2t+400=0 \\
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& \\
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& t=200\text{ s} \\
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\end{align}</math>

Revision as of 17:13, 11 October 2010

The expression for the position vector r has been obtained in part b).

r=40ti+−2t+400j 

If the aeroplane is due east of the origin its position in the north-south direction must be zero, which means the j component of the position vector must be zero.

−2t+400=0t=200 s

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