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Solution to Test Paper 2

From Mechanics

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Line 6: Line 6:
| 1 (a)
| 1 (a)
| <math>\begin{align}
| <math>\begin{align}
-
& 44.1=\frac{1}{2}\times 9.8{{t}^{2}} \\
+
& 44 \ \textrm{.}1=\frac{1}{2}\times 9 \ \ 8{{t}^{2}} \\
-
& t=\sqrt{\frac{44.1}{4.9}}=3\text{ s} \\
+
& t=\sqrt{\frac{44 \textrm{.}1}{4 \textrm{.}9}}=3\text{ s} \\
\end{align}</math>
\end{align}</math>
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<math>\begin{align}
<math>\begin{align}
-
& s=\frac{1}{2}\times 9.8\times {{3}^{2}}=44.1 \\
+
& s=\frac{1}{2}\times 9 \textrm{.}8\times {{3}^{2}}=44 \textrm{.}1 \\
& \text{AG} \\
& \text{AG} \\
& \therefore \text{Hits ground after 3 seconds} \\
& \therefore \text{Hits ground after 3 seconds} \\
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|-
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| 1 (b)
| 1 (b)
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| 2
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| <math>\begin{align}
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| 3
+
& {{v}^{2}}={{0}^{2}}+2\times 9 \textrm{.}8\times 44 \textrm{.}1 \\
-
| 4
+
& v=\sqrt{864 \textrm{.}36}=29 \ \textrm{.}4\text{ m}{{\text{s}}^{-1}} \\
 +
\end{align}</math>
 +
 
 +
OR
 +
 
 +
<math>\begin{align}
 +
& v=0+9 \textrm{.}8\times 3 \\
 +
& v=29 \textrm{.}4 \text{ m}{{\text{s}}^{-1}} \\
 +
\end{align}</math>
 +
 
 +
 
 +
|M1
 +
 
 +
A1
 +
 
 +
A1
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| (3 marks)
 +
 
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 +
| M1: Use of constant acceleration equation with <math>v=0</math>
 +
 
 +
A1: Correct equation.
 +
 
 +
A1: Correct <math>v</math>.
 +
 
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| 1 (c)
| 1 (c)
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| 2
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| Air resistance would slow the ball down.
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| 3
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| B1
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| 4
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| (1 mark)
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| B1: Sensible statement about air resistance.
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Revision as of 14:13, 19 January 2011

Solutions
1 (a) 44 .1=219  8t2t=4.944.1=3 sORs=219.832=44.1AGHits ground after 3 seconds M1

A1

A1


(M1)

(A1)

(A1)


(3 marks) M1: Use of constant acceleration

equation with v=0

A1: Correct equation

A1: Correct s


1 (b) v2=02+29.844.1v=864.36=29 .4 ms1ORv=0+9.83v=29.4 ms1M1

A1

A1


(3 marks)


M1: Use of constant acceleration equation with v=0

A1: Correct equation.

A1: Correct v.


1 (c) Air resistance would slow the ball down. B1 (1 mark) B1: Sensible statement about air resistance.
1 2 3 4 5
2 (a) 2 3 4 5
2 (b) 2 3 4 5
2 (c) 2 3 4 5
2 (d) 2 3 4 5
1 2 3 5
3 (a) 2 3 4 5
3 (b) 2 3 4 5
3 (c) 2 3 4 5
1 2 3 4 5
4 (a) 2 3 4 5
4 (b) 2 3 4 5
4 (c) 2 3 4 5
1 2 3 4 5
5 (a) 2 3 4 5
5 (b) 2 3 4 5
5 (c) 2 3 4 5