Processing Math: Done
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
jsMath

Solution 14.3

From Mechanics

(Difference between revisions)
Jump to: navigation, search
(New page: The diagram shows the forces acting. Image:14.3.gif Taking moments about the left hand support: <math>\begin{align} & {{R}_{B}}\times 3=49\times 1+196\times 1\textrm{.}5 \\ & ...)
Current revision (17:03, 10 March 2011) (edit) (undo)
 
(One intermediate revision not shown.)
Line 3: Line 3:
-
[[Image:14.3.gif]]
+
[[Image:14.3a.gif]]
Line 30: Line 30:
<math>\begin{align}
<math>\begin{align}
& {{R}_{A}}+114\textrm{.}3=49+196 \\
& {{R}_{A}}+114\textrm{.}3=49+196 \\
-
& {{R}_{A}}=49+196-114\textrm{.}3=130.7\text{ N} \\
+
& {{R}_{A}}=49+196-114\textrm{.}3=130\textrm{.}7\text{ N} \\
\end{align}</math>
\end{align}</math>

Current revision

The diagram shows the forces acting.


Image:14.3a.gif


Taking moments about the left hand support:


RB3=491+1961.5RB=3491+1961.5=114.3 N


Taking moments about the right hand support:


RA3=492+1961.5RB=3492+1961.5=130.7 N


Or:

RA+114.3=49+196RA=49+196−114.3=130.7 N

Retrieved from "http://wiki.math.se/wikis/2009/bridgecoursemechanics/index.php/Solution_14.3"