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Solution 4.5b

From Mechanics

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(New page: Image:teori4.gif Using <math>{{F}^{2}}={{H}^{2}}+{{V}^{2}}</math> and <math>\tan \alpha =\frac{V}{H} </math> Here <math>V=-3\ \text{N}</math> and <math>H=4\ \text{N}</math>....)
Current revision (11:34, 27 March 2011) (edit) (undo)
 
Line 22: Line 22:
Also
Also
-
<math>\tan \alpha =\frac{-3}{4}=B1</math>
+
<math>\tan \alpha =\frac{-3}{4}</math>
giving
giving
-
<math>\alpha =36\textrm{.}9{}^\circ</math>
+
<math>\alpha =-36\textrm{.}9{}^\circ</math>

Current revision

Image:teori4.gif

Using F2=H2+V2

and

tan=VH

Here

V=−3 N and H=4 N.

Substituting the given values

F2=42+−32=25 

giving

F=5 N

Also

tan=4−3

giving

=−36.9

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