Processing Math: Done
Solution 19.8b
From Mechanics
(Difference between revisions)
(New page: The expression for the velocity <math>\mathbf{v}</math> was obtained in part a), <math>\begin{align} & \mathbf{r}=\int{\mathbf{v}dt} \\ & \\ & =\left( 40t+{{d}_{1}} \right)\mathbf{i}+\...) |
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& t=0,\ \mathbf{r}=400\mathbf{j}\ \Rightarrow \ {{d}_{1}}=0,\ {{d}_{2}}=400 \\ | & t=0,\ \mathbf{r}=400\mathbf{j}\ \Rightarrow \ {{d}_{1}}=0,\ {{d}_{2}}=400 \\ | ||
& \\ | & \\ | ||
| - | & \mathbf{r}=\left( 40t \right)\mathbf{i}+\left( - | + | & \mathbf{r}=\left( 40t \right)\mathbf{i}+\left( {-{t}^{2}}+400 \right)\mathbf{j} |
\end{align}</math> | \end{align}</math> | ||
Current revision
The expression for the velocity
vdt=
40t+d1
i+
−t2+d2
jt=0
r=400j 
d1=0 d2=400r=40ti+−t2+400j
