Processing Math: Done
Solution to Test Paper 1
From Mechanics
(Difference between revisions)
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| 1 (a) | | 1 (a) | ||
|<math>\begin{align} | |<math>\begin{align} | ||
- | & {{0}^{2}}={{7}^{2}}+2(-\textrm{.}8)s \\ | + | & {{0}^{2}}={{7}^{2}}+2(-9\textrm{.}8)s \\ |
& s=\frac{49}{19\textrm{.}6}=2\textrm{.}5 \\ | & s=\frac{49}{19\textrm{.}6}=2\textrm{.}5 \\ | ||
& \text{Max Height }=\text{ 5}+\text{2}\text{.5}=\text{7}\text{.5 m} \\ | & \text{Max Height }=\text{ 5}+\text{2}\text{.5}=\text{7}\text{.5 m} \\ | ||
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& R=1960-0 \textrm{.}5T \\ | & R=1960-0 \textrm{.}5T \\ | ||
\end{align}</math> | \end{align}</math> | ||
+ | |||
+ | AG | ||
| (3 marks) | | (3 marks) | ||
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& \mathbf{a}=\frac{1}{10}(\mathbf{i}-5\mathbf{j})=\left( 0\textrm{.}1\mathbf{i}-0\textrm{.}5\mathbf{j} \right)\text{ m}{{\text{s}}^{\text{-2}}} \\ | & \mathbf{a}=\frac{1}{10}(\mathbf{i}-5\mathbf{j})=\left( 0\textrm{.}1\mathbf{i}-0\textrm{.}5\mathbf{j} \right)\text{ m}{{\text{s}}^{\text{-2}}} \\ | ||
\end{align}</math> | \end{align}</math> | ||
- | | (3 marks) | + | |
+ | | (3 marks) | ||
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|} | |} | ||
+ | |||
+ | AG: Answer Given in Question – Working must justify answer. |
Current revision
AG: Answer Given in Question – Working must justify answer.