Processing Math: Done

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Line 60:		Line 60:
	|-		|-
	|8 N		|8 N
-	|valign="top"| <math>-8\times 1.2=-9.6</math>	+	|valign="top"| <math>-8\times 1\textrm{.}2=-9\textrm{.}6</math>
	|-		|-
Line 69:		Line 69:
	|-		|-
	|6 N		|6 N
-	| valign="top"| <math>-6\times 0.5=-3</math>	+	| valign="top"| <math>-6\times 0\textrm{.}5=-3</math>
	|-		|-
	|5 N		|5 N
-	| valign="top"| <math>5\times 1.2=6</math>	+	| valign="top"| <math>5\times 1\textrm{.}2=6</math>
	|-		|-
	|4 N		|4 N
-	| valign="top"| <math>4\times 0.5=2</math>	+	| valign="top"| <math>4\times 0\textrm{.}5=2</math>
	|-		|-
	|Total Moment		|Total Moment
-	| valign="top"| <math>0-9.6+0-3+6+2=-4.6\text{ Nm}</math>	+	| valign="top"| <math>0-9\textrm{.}6+0-3+6+2=-4\textrm{.}6\text{ Nm}</math>
	|}		|}

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Revision as of 09:39, 23 September 2009

Theory

Exercises

Key Points

The moment of the force about the point O is the product of the force and the perpendicular distance to the line of action of the force from O.

Moment =Fd

Moment =Fdsin

Clockwise moments are negative. Anti-clockwise moments are positive.

Example 13.1

Example 13.2

Example 13.3

For the rectangular lamina shown below, find the total moment of the forces acting, about the corner marked O.

Solution

Force	Moment
5N at O	50=0
8 N	−81.2=−9.6
7 N	70=0
6 N	−60.5=−3
5 N	51.2=6
4 N	40.5=2
Total Moment	0−9.6+0−3+6+2=−4.6 Nm