From Mechanics

Revision as of 09:58, 23 March 2010 (edit) Ian (Talk | contribs) (New page: Image:teori4.gif Using <math>{{F}^{2}}={{H}^{2}}+{{V}^{2}}</math> Substituting the given values <math>\begin{align} & {{F}^{2}}={{4}^{2}}+{ {3}^{2}} =25 \\ & F=5 \text{ N} \\ \end...) ← Previous diff		Revision as of 10:35, 23 March 2010 (edit) (undo) Ian (Talk | contribs) Next diff →
Line 2:		Line 2:
	Using <math>{{F}^{2}}={{H}^{2}}+{{V}^{2}}</math>		Using <math>{{F}^{2}}={{H}^{2}}+{{V}^{2}}</math>
		+
		+	and
		+
		+	<math>\tan \alpha =\frac{V}{H} </math>
		+
		+	Here
		+
		+	<math>V=A</math> and
		+	<math>H=B</math>.
	Substituting the given values		Substituting the given values
		+
	<math>\begin{align}		<math>\begin{align}
-	& {{F}^{2}}={{4}^{2}}+{	+	& {{F}^{2}}={{4}^{2}}+{{3}^{2}}=25 \\
-	{3}^{2}}	+	& \text{giving} \\
-	=25 \\	+	& F=5\ \text{N} \\
-	& F=5 \text{ N} \\	+
	\end{align}</math>		\end{align}</math>
-	<math>\tan \alpha =\frac{V}{H}</math>
-	Here	+	Also
-	<math>V=3\ \text{N}</math>	+
-	and	+
-	<math>H=4\ \text{N}</math>.	+
-		+
-	Thus	+
	<math>\tan \alpha =\frac{3}{4}=0\textrm{.}75</math>		<math>\tan \alpha =\frac{3}{4}=0\textrm{.}75</math>
		+
	giving		giving
		+
	<math>\alpha =36\textrm{.}9{}^\circ</math>		<math>\alpha =36\textrm{.}9{}^\circ</math>

---

Revision as of 10:35, 23 March 2010

Using \displaystyle {{F}^{2}}={{H}^{2}}+{{V}^{2}}

and

\displaystyle \tan \alpha =\frac{V}{H}

Here

\displaystyle V=A and \displaystyle H=B.

Substituting the given values

\displaystyle \begin{align} & {{F}^{2}}={{4}^{2}}+{{3}^{2}}=25 \\ & \text{giving} \\ & F=5\ \text{N} \\ \end{align}

Also

\displaystyle \tan \alpha =\frac{3}{4}=0\textrm{.}75

giving

\displaystyle \alpha =36\textrm{.}9{}^\circ