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Solution 16.10b

From Mechanics

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(New page: From part a) <math>(5m+2\lambda m-3m-3\lambda m)\mathbf{i}+(mV-\lambda mV+2m+2\lambda m)\mathbf{j}=0\mathbf{i}+0\mathbf{j}</math> Consider the <math>\mathbf{j}</math> component. That is...)
Current revision (16:43, 27 March 2011) (edit) (undo)
 
Line 13: Line 13:
& V=6 \\
& V=6 \\
\end{align}</math>
\end{align}</math>
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Note that <math>V</math> is a dimensionless number.
 

Current revision

From part a)

(5m+2m−3m−3m)i+(mV−mV+2m+2m)j=0i+0j

Consider the j component. That is the j component on the left hand side must be the same as the j component on the right hand side, that is zero.

mV−mV+2m+2m=0V−2V+2+4=0−V+6=0V=6

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