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Solution to Test Paper 2
From Mechanics
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| 1 (a) | | 1 (a) | ||
| <math>\begin{align} | | <math>\begin{align} | ||
- | & 44 | + | & 44\textrm{.}1=\frac{1}{2}\times 9\textrm{.}8{{t}^{2}} \\ |
- | & t=\sqrt{\frac{44 | + | & t=\sqrt{\frac{44\textrm{.}1}{4\textrm{.}9}}=3\text{ s} \\ |
- | \ | + | & \\ |
- | + | & \text{OR} \\ | |
- | + | & \\ | |
- | + | & s=\frac{1}{2}\times 9\textrm{.}8\times {{3}^{2}}=44\textrm{.}1 \\ | |
- | + | ||
- | & s=\frac{1}{2}\times 9 | + | |
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& \therefore \text{Hits ground after 3 seconds} \\ | & \therefore \text{Hits ground after 3 seconds} \\ | ||
\end{align}</math> | \end{align}</math> | ||
- | + | AG | |
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| 1 (b) | | 1 (b) | ||
| <math>\begin{align} | | <math>\begin{align} | ||
- | & {{v}^{2}}={{0}^{2}}+2\times 9 | + | & {{v}^{2}}={{0}^{2}}+2\times 9\textrm{.}8\times 44\textrm{.}1 \\ |
- | & v=\sqrt{864 \textrm{.}36}=29 | + | & v=\sqrt{864\textrm{.}36}=29\textrm{.}4m \\ |
+ | & \\ | ||
+ | & \text{OR} \\ | ||
+ | & \\ | ||
+ | & v=0+9\textrm{.}8\times 3 \\ | ||
+ | & v=29\textrm{.}4 \\ | ||
\end{align}</math> | \end{align}</math> | ||
- | OR | ||
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- | <math>\begin{align} | ||
- | & v=0+9 \textrm{.}8\times 3 \\ | ||
- | & v=29 \textrm{.}4 \text{ m}{{\text{s}}^{-1}} \\ | ||
- | \end{align}</math> | ||
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& 800-900=2000a \\ | & 800-900=2000a \\ | ||
& a=\frac{-100}{2000}=-0\textrm{.}05 \text{ m}{{\text{s}}^{-2}} \\ | & a=\frac{-100}{2000}=-0\textrm{.}05 \text{ m}{{\text{s}}^{-2}} \\ | ||
+ | & \text{Car is slowing down} \\ | ||
\end{align}</math> | \end{align}</math> | ||
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| '''(8 marks)''' | | '''(8 marks)''' | ||
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Current revision
KEY M1: Method Mark
A1: Accuracy Mark following a method mark
B1: Accuracy Mark not following a method mark
AG: Answer Given in Question – Working must justify answer.
TOTAL: 40 Marks