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Solution to Test Paper 2

From Mechanics

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| '''(7 marks)'''
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| 2 (a)
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| [[Image:test2ans2.gif]]
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| B1
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| (1 mark)
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| B1: Correct horizontal forces.
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Ignore any vertical forces.
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| 2 (b)
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| <math>P = 900 \text{N}</math>
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| B1
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| (1 mark)
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| B1: Correct value for <math>P</math>.
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| 2 (c)
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| <math>\begin{align}
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& P-900=2000\times 1\textrm{.}2 \\
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& P=2400+900=3300 \text{N} \\
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\end{align}</math>
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| M1
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A1
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A1
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| (1 mark)
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| M1: Three term equation of motion
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A1: Correct equation
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A1: Correct <math>P</math>.
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| 2 (d)
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| <math>\begin{align}
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& 800-900=2000a \\
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& a=\frac{-100}{2000}=-0\textrm{.}05 \text{ m}{{\text{s}}^{-2}} \\
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\end{align}</math>
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Car is slowing down
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| M1
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A1
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A1
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A1
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| (4 marks)
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| M1: Three term equation of motion
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A1: Correct equation
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A1: Correct <math>a</math>
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A1: Correct statement
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Revision as of 15:00, 19 January 2011

Solutions
1 (a) 44 .1=219  8t2t=4.944.1=3 sORs=219.832=44.1AGHits ground after 3 seconds M1

A1

A1


(M1)

(A1)

(A1)


(3 marks) M1: Use of constant acceleration

equation with v=0

A1: Correct equation

A1: Correct s


1 (b) v2=02+29.844.1v=864.36=29 .4 ms−1ORv=0+9.83v=29.4 ms−1M1

A1

A1


(3 marks)


M1: Use of constant acceleration equation with v=0

A1: Correct equation.

A1: Correct v.


1 (c) Air resistance would slow the ball down. B1 (1 mark) B1: Sensible statement about air resistance.
(7 marks)
2 (a) Image:test2ans2.gif B1 (1 mark) B1: Correct horizontal forces.

Ignore any vertical forces.


2 (b) P=900N B1 (1 mark) B1: Correct value for P.
2 (c) P−900=20001.2P=2400+900=3300N M1

A1

A1

(1 mark) M1: Three term equation of motion

A1: Correct equation

A1: Correct P.


2 (d) 800−900=2000aa=2000−100=−0.05 ms−2Carisslowingdown M1

A1

A1

A1

(4 marks) M1: Three term equation of motion

A1: Correct equation

A1: Correct a

A1: Correct statement


(9 marks)
3 (a) 2 3 4 5
3 (b) 2 3 4 5
3 (c) 2 3 4 5
1 2 3 4 5
4 (a) 2 3 4 5
4 (b) 2 3 4 5
4 (c) 2 3 4 5
1 2 3 4 5
5 (a) 2 3 4 5
5 (b) 2 3 4 5
5 (c) 2 3 4 5


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