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Solution 16.5

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(New page: Using <math>{{m}_{A}}{{v}_{A}}+{{m}_{B}}{{v}_{B}}={{m}_{A}}{{u}_{A}}+{{m}_{B}}{{u}_{B}}</math> Assume the 2 kg particle is moving in the positive direction, <math>\begin{align} & 2\time...)
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Revision as of 17:07, 23 September 2010

Using

mAvA+mBvB=mAuA+mBuB

Assume the 2 kg particle is moving in the positive direction,

25+3(6)=2(2)+3v1012=4+3v2=3vv=32 ms-1

The 3 kg particle moves in the opposite direction to its original velocity.