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Solution 16.7b

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Ian (Talk | contribs)
(New page: From part a), <math>\mathbf{v}=2\textrm{.}5\mathbf{i}+4\mathbf{j}</math> which gives, <math>\begin{align} & \tan \alpha =\frac{4}{2\textrm{.}5} \\ & \alpha =58\textrm{.}0{}^\circ \\ \...)
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Revision as of 18:57, 23 September 2010

From part a),

v=2.5i+4j which gives,

tan=42.5=58.0