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Solution 16.10a

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(New page: <math>\begin{align} & m(4\mathbf{i}+V\mathbf{j})+\lambda m(2\mathbf{i}-V\mathbf{j})=(m+\lambda m)(3\mathbf{i}+2\mathbf{j}) \\ & (4m+2\lambda m-3m)\mathbf{i}+(mV-\lambda mV-2\lambda m)\mat...)
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Revision as of 17:39, 29 September 2010

m(4i+Vj)+m(2i−Vj)=(m+m)(3i+2j)(4m+2m−3m)i+(mV−mV−2m)j=0i+0j

Consider the i component. That is the i component on the left hand side must be the same as the i component on the right hand side.

3m+2m−4=02−1=0=21

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