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Solution 20.4a

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(New page: Converting the angular speed to standard units. <math>\omega =30\text{ rpm }=\frac{30\times 2\pi }{60}=\pi \text{ rad}{{\text{s}}^{\text{-1}}}</math> For circular motion: <math>\begin{a...)
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Converting the angular speed to standard units.

=30 rpm =60302= rads-1

For circular motion:

F=mr2=0.020.252=0.0493 N

The force R on the coin normal to the surface is

R=9.80.02=0.196 N

Using the friction inequality for the coin to remain at rest on the surface:

FRF0.60.196F0.1176 N

As 0.0493 is less than 0.1176 the coin remains in the same position on the turntable.