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Solution 20.4a
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(New page: Converting the angular speed to standard units. <math>\omega =30\text{ rpm }=\frac{30\times 2\pi }{60}=\pi \text{ rad}{{\text{s}}^{\text{-1}}}</math> For circular motion: <math>\begin{a...)
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Converting the angular speed to standard units.
=30 rpm =6030
2
=
rads-1
For circular motion:
2=0.02
0.25
2=0.0493 N
The force
0.02=0.196 N
Using the friction inequality for the coin to remain at rest on the surface:
RF
0.6
0.196F
0.1176 N
As 0.0493 is less than 0.1176 the coin remains in the same position on the turntable.