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Solution 20.4b

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(New page: If <math>F=\mu R</math> then the coin can remain on the surface. This is the maximum value that <math>F</math> can take. That is <math>mr{{\omega }^{2}}=\mu R</math>. This gives <math>\...)
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If F=R then the coin can remain on the surface. This is the maximum value that F can take.

That is mr2=R.

This gives

0.02r2=0.1176r=0.11760.022=0.596 m or 59.6 cm

Note that for values of r greater than this the frictional force cannot keep the coin from sliding.