Processing Math: 80%
To print higher-resolution math symbols, click the
Hi-Res Fonts for Printing button on the jsMath control panel.
No jsMath TeX fonts found -- using image fonts instead.
These may be slow and might not print well.
Use the jsMath control panel to get additional information.
jsMath Control PanelHide this Message

jsMath

Solution to Test Paper 2

From Mechanics

(Difference between revisions)
Jump to: navigation, search
Line 6: Line 6:
| 1 (a)
| 1 (a)
| <math>\begin{align}
| <math>\begin{align}
-
& 44 \ \textrm{.}1=\frac{1}{2}\times 9 \ \ 8{{t}^{2}} \\
+
& 44 \ \textrm{.}1=\frac{1}{2}\times 9 \textrm{.} 8{{t}^{2}} \\
& t=\sqrt{\frac{44 \textrm{.}1}{4 \textrm{.}9}}=3\text{ s} \\
& t=\sqrt{\frac{44 \textrm{.}1}{4 \textrm{.}9}}=3\text{ s} \\
\end{align}</math>
\end{align}</math>
Line 218: Line 218:
|-
|-
| 4 (a)
| 4 (a)
-
| 2
+
| [[Image:test2ans4.gif]]
| 3
| 3
| 4
| 4

Revision as of 15:59, 19 January 2011

Solutions
1 (a) 44 .1=219.8t2t=4.944.1=3 sORs=219.832=44.1AGHits ground after 3 seconds M1

A1

A1


(M1)

(A1)

(A1)


(3 marks) M1: Use of constant acceleration

equation with v=0

A1: Correct equation

A1: Correct s


1 (b) v2=02+29.844.1v=864.36=29 .4 ms−1ORv=0+9.83v=29.4 ms−1M1

A1

A1


(3 marks)


M1: Use of constant acceleration equation with v=0

A1: Correct equation.

A1: Correct v.


1 (c) Air resistance would slow the ball down. B1 (1 mark) B1: Sensible statement about air resistance.
(7 marks)
2 (a) Image:test2ans2.gif B1 (1 mark) B1: Correct horizontal forces.

Ignore any vertical forces.


2 (b) P=900N B1 (1 mark) B1: Correct value for P.
2 (c) P−900=20001.2P=2400+900=3300N M1

A1

A1

(1 mark) M1: Three term equation of motion

A1: Correct equation

A1: Correct P.


2 (d) 800−900=2000aa=2000−100=−0.05 ms−2Carisslowingdown M1

A1

A1

A1

(4 marks) M1: Three term equation of motion

A1: Correct equation

A1: Correct a

A1: Correct statement


(9 marks)
3 (a) R=209.8=196 N M1

A1

(2 marks) M1: Use of R=mg

A1: Correct R.


3 (b) F=0.4196=78.4 N M1

A1

(2 Marks) M1: Use of \displaystyle F=\mu R

A1: Correct \displaystyle F.


3 (c) \displaystyle \begin{align}

& 100-78 \textrm{.}4=20a \\ & a=\frac{100-78 \textrm{.}4}{20}=1 \textrm{.}08 \text{ m}{{\text{s}}^{-2}} \\ \end{align}

M1

A1

A1

(3 marks) M1: Three term equation of motion

A1: Correct equation

A1: Correct \displaystyle a.


(8 marks)
4 (a) Image:test2ans4.gif 3 4 5
4 (b) 2 3 4 5
4 (c) 2 3 4 5
1 2 3 4 5
5 (a) 2 3 4 5
5 (b) 2 3 4 5
5 (c) 2 3 4 5


Retrieved from "http://wiki.math.se/wikis/2009/bridgecoursemechanics/index.php/Solution_to_Test_Paper_2"