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Solution 4.6c

From Mechanics

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Current revision (16:13, 4 February 2011) (edit) (undo)
 
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Thus
Thus
-
<math>\tan \alpha =\frac{-11\textrm{.}3}{80.9}=-0\textrm{.}14</math>
+
<math>\tan \alpha =\frac{-11\textrm{.}3}{80\textrm{.}9}=-0\textrm{.}14</math>
giving
giving

Current revision

Resultant force =80.9i11.3j N

Thus

tan=80.911.3=0.14

giving

=8.0

As the vector is in the fourth quadrant

Image:4.6c.gif