Processing Math: Done
Solution 5.5b
From Mechanics
(Difference between revisions)
| Line 8: | Line 8: | ||
<math>\begin{align} | <math>\begin{align} | ||
| - | & N=mg-5000\cos {{65}^{\circ }}=500\times 9.8-5000\times 0.423 \\ | + | & N=mg-5000\cos {{65}^{\circ }}=500\times 9\textrm{.}8-5000\times 0\textrm{.}423 \\ |
& =4900-2113=2787\ \text{N} \\ | & =4900-2113=2787\ \text{N} \\ | ||
\end{align}</math> | \end{align}</math> | ||
Current revision
In the vertical direction the forces on the tank must be in equilibrium.
−mg+N+5000cos65
=0
or
=500
9.8−50000.423=4900−2113=2787 N
