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Solution 14.3

From Mechanics

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Current revision (17:03, 10 March 2011) (edit) (undo)
 
Line 30: Line 30:
<math>\begin{align}
<math>\begin{align}
& {{R}_{A}}+114\textrm{.}3=49+196 \\
& {{R}_{A}}+114\textrm{.}3=49+196 \\
-
& {{R}_{A}}=49+196-114\textrm{.}3=130.7\text{ N} \\
+
& {{R}_{A}}=49+196-114\textrm{.}3=130\textrm{.}7\text{ N} \\
\end{align}</math>
\end{align}</math>

Current revision

The diagram shows the forces acting.


Image:14.3a.gif


Taking moments about the left hand support:


RB3=491+1961.5RB=3491+1961.5=114.3 N


Taking moments about the right hand support:


RA3=492+1961.5RB=3492+1961.5=130.7 N


Or:

RA+114.3=49+196RA=49+196114.3=130.7 N