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Answer 18.1c

From Mechanics

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(New page: <math>t=0\text{ }\ \text{ or } \text{ } \ t=\frac{40}{3}=13\textrm{.}3</math>)
Current revision (16:54, 27 March 2011) (edit) (undo)
 
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<math>t=0\text{ }\ \text{ or } \text{ } \ t=\frac{40}{3}=13\textrm{.}3</math>
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<math>t=0\text{ }\ \text{ or } \text{ } \ t=10</math>

Current revision

t=0   or  t=10

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