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Solution to Test Paper 3

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(New page: {| border="1" |+ Solutions | 1 (a) |<math>\begin{align} & 0=24.5-9.8t \\ & t=\frac{24.5}{9.8}=2.5\text{ seconds} \\ \end{align}</math> | (3 marks) |- | 1 (b) | <math>\begin{align} ...)
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Revision as of 15:45, 4 April 2012

Solutions
1 (a) 0=245−98tt=98245=25 seconds (3 marks)


1 (b) 02=2452+2(−98)ss=2452298=30625 mORs=21(245+0)25=30625 m (3 marks)
(6 marks)


2 (a) T−8009.8=8000.2T=7840+160=8000 N (3 marks)


2 (b) T−8009.8=800(−0.2)T=7840−160=7680 N (3 marks)


2 (c) T=8009.8=7840 N (1 mark)


(7 marks)


3 (a) Image:test1ans1.gif (1 mark)


3 (b) F=21.8=3.6 N (2 marks)


3 (c) R=29.8=19.6 N (2 marks)


3 (d) 3.6=19.6=3.619.6=0.184 (3 marks)


(8 marks)


4 (a) Image:test1ans2.gif (1 mark)


4 (b) R+Tsin30=2009.8R+0.5T=1960R=1960−0.5T (3 marks)


4 (c)

F=Tcos30Tcos30=0.6(1960−0.5T)T(cos30+0.3)=1176T=1176(cos30+0.3)=1010 N

(4 marks)


(8 marks)


5 (a) 5i−2j=4i+3j+10aa=110(i−5j)=0.1i−0.5j ms-2AG  (3 marks)


5 (b) r=(4i+3j)t+0.5(0.1i−0.5j)t2 (2 marks)


5 (c) r=(4t+0.05t2)i+(3t−0.25t2)j3t−0.25t2=0t(3−0.25t)=0t=0 or t=30.25=12 st=12 s (3 marks)


5 (d) v=(4+0.1t)i+(3−0.5t)j3−0.5t=0t=6 s (3 marks)


(11 marks)


AG: Answer Given in Question – Working must justify answer.

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