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Solution to Test Paper 3

From Mechanics

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| [[Image:test3ans1.gif]]
| [[Image:test3ans1.gif]]
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| (3 marks)
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| (1 marks)
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| T = 4900 N
| T = 4900 N
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| (3 marks)
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| (1 marks)
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\end{align}</math>
\end{align}</math>
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| (1 mark)
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| (3 mark)
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|-
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| 3 (d)
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| <math>\begin{align}
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& 4800-4900=500a \\
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& a=\frac{-100}{500}=-0.2\text{ m}{{\text{s}}^{\text{-2}}} \\
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& 0.\text{2 m}{{\text{s}}^{-\text{2}}}\quad \text{downwards} \\
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\end{align}</math>
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| (4 mark)
|-
|-
|
|
|
|
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| '''(7 marks)'''
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| '''(9 marks)'''

Revision as of 09:09, 8 April 2012

Solutions
1 (a) 0=245−98tt=98245=25 seconds (3 marks)


1 (b) 02=2452+2(−98)ss=2452298=30625 mORs=21(245+0)25=30625 m (3 marks)
1 (c) 61.25 m


(1 marks)
(7 marks)


2 (a) Image:test3ans1.gif (1 marks)


2 (b) T = 4900 N (1 marks)


2 (c) T−4900=50006T=300+4900=5200 N (3 mark)
3 (d) 4800−4900=500aa=500−100=−02 ms-202 ms−2downwards (4 mark)
(9 marks)


3 (a) Image:test1ans1.gif (1 mark)


3 (b) F=21.8=3.6 N (2 marks)


3 (c) R=29.8=19.6 N (2 marks)


3 (d) 4800−4900=500aa=500−100=−02 ms-202 ms−2downwards (3 marks)


(8 marks)


4 (a) Image:test1ans2.gif (1 mark)


4 (b) R+Tsin30=2009.8R+0.5T=1960R=1960−0.5T (3 marks)


4 (c)

F=Tcos30Tcos30=0.6(1960−0.5T)T(cos30+0.3)=1176T=1176(cos30+0.3)=1010 N

(4 marks)


(8 marks)


5 (a) 5i−2j=4i+3j+10aa=110(i−5j)=0.1i−0.5j ms-2AG  (3 marks)


5 (b) r=(4i+3j)t+0.5(0.1i−0.5j)t2 (2 marks)


5 (c) r=(4t+0.05t2)i+(3t−0.25t2)j3t−0.25t2=0t(3−0.25t)=0t=0 or t=30.25=12 st=12 s (3 marks)


5 (d) v=(4+0.1t)i+(3−0.5t)j3−0.5t=0t=6 s (3 marks)


(11 marks)


AG: Answer Given in Question – Working must justify answer.

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