Part 1
What is a force?
Force and gravity
Other forces
Forces and vectors
Part 2
Forces and equilibrium
Kinematics
Position Vectors
Constant acceleration
Part 3
Newton’s first law
Newton’s second law
Newton’s third law
Mathematical modelling
Practice tests
Practice Test Paper 1
Solution to Test Paper 1
Practice Test Paper 2
Solution to Test Paper 2
Practice Test Paper 3
Solution to Test Paper 3
Part 4
Moments
Equilibrium
Momentum and impulse
Conservation of momentum
Part 5
Conservation of energy
Variable acceleration I
Variable acceleration II
Circular Motion
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Solution to Test Paper 3
From Mechanics
Revision as of 09:20, 8 April 2012 by
Ian
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Solutions
1 (a)
0
=
2
4
5
−
9
8
t
t
=
9
8
24
5
=
2
5
seconds
(3 marks)
1 (b)
0
2
=
24
5
2
+
2
(
−
9
8)
s
s
=
24
5
2
2
9
8
=
3
0
625
m
O
R
s
=
2
1
(24
5
+
0
)
2
5
=
3
0
625
m
(3 marks)
1 (c)
61.25 m
(1 marks)
(7 marks)
2 (a)
(1 marks)
2 (b)
T = 4900 N
(1 marks)
2 (c)
T
−
4
900
=
5
00
0
6
T
=
3
00
+
4
900
=
5
200
N
(3 mark)
3 (d)
4800
−
4
900
=
5
00
a
a
=
500
−
100
=
−
0
2
ms
-2
0
2 ms
−
2
downwards
(4 mark)
(9 marks)
3 (a)
R
=
5
9
8
cos
4
2
=
3
6
4
N
(2 mark)
3 (b)
F
=
0
4
R
=
1
4
6
N
(2 marks)
3 (c)
5
9
8
sin
4
2
−
1
4
6
=
5
a
a
=
5
18
22
=
3
64
ms
-2
(3 marks)
3 (d)
2
=
2
1
3
64
t
2
t
=
4
3
64
=
1
05
seconds
(3 marks)
(10 marks)
4 (a)
Q
cos
4
0
=
8
9
8
sin
4
0
Q
=
cos
4
0
8
9
8
sin
4
0
=
6
5
8
N
(3 mark)
4 (b)
Q
cos
4
0
+
F
=
8
9
8
sin
4
0
Q
sin
4
0
+
8
9
8
cos
4
0
=
R
Q
cos
4
0
=
8
9
8
sin
4
0
−
0
3(
Q
sin
4
0
+
8
9
8
cos
4
0
)
Q
=
cos
4
0
+
0
3
sin
4
0
8
9
8
sin
4
0
−
0
3
8
9
8
cos
4
0
=
3
3
8
N
(5 marks)
(8 marks)
5 (a)
v
=
(
i
+
j
)
+
(
0
05
i
−
0
1
j
)
t
(2 marks)
5 (b)
−
(1
+
0
05
t
)
=
1
−
0
1
t
0
05
t
=
2
t
=
4
0
(4 marks)
(6 marks)