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Solution 8.4a
From Mechanics
Here we have a=0.2i+0.3j
u=4i–8j and r0=6i+2j.
Using v=u+at at t=10 gives
v=4i–8j+(0.2i+0.3j)
10 or
v=6i–5j ms−1
The speed is the magnitude of this velocity vector.
v=
62+
−5
2=
61=7.8 ms−1