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Solution 8.6b

From Mechanics

Revision as of 19:57, 14 April 2010 by Ian (Talk | contribs)
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Here we use

r=21(u+v)t+r0

in the first part.

According to the text

u=i+2j

v=6i8j

We assume the starting point is the origin so that r0=0.

At t=10

r=21(i+2j+6i8j)t=(3.5i3j)10=35i30j=(7i6j)5

The distance is the magnitude of this vector

72+62=13=3.6 m 

In the second part the boat travel with constant velocity 6i8j



Thus during the first part the boat has travelled a distance 3.6 m.