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Solution 16.10a

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m(4i+Vj)+m(2iVj)=(m+m)(3i+2j)(4m+2m3m)i+(mVmV2m)j=0i+0j

Consider the i component. That is the i component on the left hand side must be the same as the i component on the right hand side.

3m+2m4=021=0=21