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Solution 2.8

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Revision as of 16:12, 3 February 2011 by Ian (Talk | contribs)
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Consider a particle on the surface of the planet.

F=d2Gm1m2

where F is the gravitational force on a particle on the surface of the planet, in other words, its weight.

m1 is the mass of the planet, m2 is the mass of the particle and d is the radius of the planet.

As F=m2a where a is the acceleration of the particle very close to the surface of the planet,


a=d2Gm1

Thus

d2=aGm1

As G=6.671011 kg-1m3s-2 we get


d2=3.26.67101151020=3.233.35109=10.4109=1.041010d=1.04105=1.02105 m=102 km