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Solution to Test Paper 3

From Mechanics

Revision as of 09:20, 8 April 2012 by Ian (Talk | contribs)
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Solutions
1 (a) 0=245−98tt=98245=25 seconds (3 marks)


1 (b) 02=2452+2(−98)ss=2452298=30625 mORs=21(245+0)25=30625 m (3 marks)
1 (c) 61.25 m


(1 marks)
(7 marks)


2 (a) Image:test3ans1.gif (1 marks)


2 (b) T = 4900 N (1 marks)


2 (c) T−4900=50006T=300+4900=5200 N (3 mark)
3 (d) 4800−4900=500aa=500−100=−02 ms-202 ms−2downwards (4 mark)
(9 marks)


3 (a) R=598cos42=364 N (2 mark)


3 (b) F=04R=146 N (2 marks)


3 (c) 598sin42−146=5aa=51822=364 ms-2 (3 marks)


3 (d) 2=21364t2t=4364=105 seconds  (3 marks)


(10 marks)


4 (a) Qcos40=898sin40Q=cos40898sin40=658 N (3 mark)


4 (b) Qcos40+F=898sin40Qsin40+898cos40=RQcos40=898sin40 −03(Qsin40+898cos40)Q=cos40+03sin40898sin40−03898cos40 =338 N (5 marks)



(8 marks)


5 (a) v=(i+j)+(005i−01j)t


(2 marks)


5 (b) −(1+005t)=1−01t005t=2t=40 (4 marks)



(6 marks)


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